The plates of a parallel plate capacitor have an area of `90cm^(2)` each and are separated by a `2mm` The capacitor is charged by connecting it to a `400V` supply.Then the density of the energy stored in the capacitor ..........?

The plates of a parallel plate capacitor have an area of 90cm^(2) and each are separated by 2mm. The capacitor is charged by connecting it to a 400 V supply. Then the energy density of the energy stored (in Jm^(-3) ) in the capacitor is (take epsi_(0)=8.8xx10^(-12)Fm^(-1) )

The plates of a paralllel plate capacitor have an area of 90 cm^(2) each and are separated by 2.5mm. The capacitane is charged by connecting it to a 400V supply. (a) How much electrostatic energy is stored by the capacitor ? (b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume (u). Hence arrive at a realtion between U and the magnitude of electric field E between the plates.

The plates of a parallel plate capacitor have an area of 100cm^(2) each and area separated by 2.5 mm. the capacitor is charged to 200V. Calculate the energy stored in the capacitor.

The plates of a parallel plate capacitor have on area of 90 cm^(2) each and are separated by 2.5 mm . The capacitor is charged to 400 V. How much electrostatic energy is stored in it ? How much when it is filled with a dielectric medium K = 3 and then charged ? If it is first charged as an air capacitor and then filled with th dielectric, then ?

A parallel plate capacitor having a plate separation of 2mm is charged by connecting it to a 300v supply. The energy density is

A parallel plate capacitor has plates of area 4 m^2 separated by distance of 0.5 mm. The capacitor is connected across a cell of emf 100 V. Find the capacitance, charge and energy stored in the capacitor.

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,