The radical center of the circles `x^(2)+y^(2)-4x-6y+5=0`,`x^(2)+y^(2)-2x-4y-1=0`,`x^(2)+y^(2)-6x-2y=0`.

Find the radical center of the circles x^(2)+y^(2)+4x+6y=19,x^(2)+y^(2)=9,x^(2)+y^(2)-2x-4y=5

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

The circles x^(2)+y^(2)+6x+6y=0 and x^(2)+y^(2)-12x-12y=0

The circumcentre of the triangle made by the line segments joining the centres of the circles x^(2)+y^(2)-4=0;x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)-6x-2y+6=0

The circles x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)+4y-1 =0

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 , x^(2)+y^(2)+8x-4y+11=0

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 ,x^(2)+y^(2)+8x-4y+11=0

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 ,x^(2)+y^(2)+8x-4y+11=0

The circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+4x+6y+4=0