A family of lines is given by `(1 +3lambda)x + 2lambda y-1 (1-3lambda) = 0.` If one of the bisectors of two of the members of the family has equation `x+y+2=0.` Find the equation of other bisector

A family of lines is given by (1+2lambda)x+(1-lambda)y+lambda=0 being a parameter . The line belonging to this family at the maximum distance from the point (1,4) is ax+by+c=0 , then find the value of (a+b+c)/16

A family of lines is given by (1+2 lambda)x+(1-lambda)y+lambda=0 being a parameter.The line belonging to this family at the maximum distance from the point (1,4) is ax+by+c=0, then find the value of (a+b+c)/(16)

One bisector of the angle between the lines given by a(x-1)^(2)+2h(x-1)y+by^(2)=0 is 2x+y-2=0 . The equation of the other bisector is

One bisector of the angle between the lines given by a(x-1)^(2)+2h(x-1)y+by^(2)=0 is 2x+y-2=0 . The equation of the other bisector is

A member of the family of lines (x+ y -1) + lambda(2x +3y-2) =0, lambda in R intersects a member of the family of lines (ax+y-2) + alpha(bx + 4y-5) = 0, alpha in R , at a fixed point. The ordered pair (a, b) is

If one angular bisector of a(x+1)^(2)+2h(x+1)(y-3)+b(y-3)^(2)=0 is 2x-3y+11=0 then equation of other angular bisector is

If one angular bisector of a(x+1)^(2)+2h(x+1)(y-3)+b(y-3)^(2)=0 is 2x-3y+11=0 then equation of other angular bisector is

Consider a set of all the lines (2 + lambda)x - (3 + 2lambda)y + (1 + lambda) = 0, lambda in R , then equation of the line which belongs to this set & farthest from origin is :

Consider a set of all the lines (2 + lambda)x - (3 + 2lambda)y + (1 + lambda) = 0, lambda in R , then equation of the line which belongs to this set & farthest from origin is :

Given 2x+4y+z=1,lambda x+2y+z=2,x+y-lambda z=3 then one of the value of a such that the given system of equations has no solution,is