" If vector "vec b" is collinear with vectoraี "=(2sqrt(2),-1,4)" and "|vec b|=10" ,then "

If the vector vec b is collinear with the vector vec a(2sqrt(2),-1,4) and |vec b|=10, then

Section (A): Position vector,Direction Ratios & Direction cosines: A^(-1). If the vector vec b is collinear with the vect,vec a=(2sqrt(2),-1,4) and |vec b|=6 then:

If the vector vecb is collinear with the vector vec a =( 2sqrt2,-1,4) and |vecb| =10 , then

If the vector vecb is collinear with the vector vec a ( 2sqrt2,-1,4) and |vecb| =10 , then

If the vector vecb is collinear with the vector vec a ( 2sqrt2,-1,4) and |vecb| =10 , then

If the vector vec(b) is collinear to the vector bar(a) and bar(a)=(2sqrt(2),-1,4) and |vec(b)|=10 then ……………

A vecotr vec(b) is collinear with the vector vec(a)= (2, 1, -1) and satisfies the condition vec(a). vec(b)= 3 . What is vec(b) equal to ?

Find the vector a which is collinear with the vector vec b=2hat i-hat j and vec a*vec b=10

Three non-zero vectors vec(a), vec(b), vec(c) are such that no two of them are collinear. If the vector (vec(a)+vec(b)) is collinear with the vector vec(c) and the vector (vec(b)+vec(c)) is collinear with vector vec(a) , then prove that (vec(a)+vec(b)+vec(c)) is a null vector.

If vec a and vec b are non-collinear unit vectors and |vec a+vec b|=sqrt(3) then (2vec a+5vec b)*(3vec a-vec b)=