" (ii) "sin(50^(@)+theta)-cos(40^(@)-theta)

Prove that (i) sin(40^(@)-theta)-cos(50^(@)+theta)=0 (ii) sec(65^(@)+theta)-"cosec"(25^(@)-theta)=0

Prove that (i) sin(40^(@)-theta)cos(50^(@)+theta)=0 (ii) 1sec(65^(@)+theta)-"cesec"(25^(@)-theta)=0

Evaluate sin (50^(@) + theta) - cos (40^(@) - theta) + tan 1^(@) tan 15^(@) tan 20^(@) tan 70^(@) tan 65^(@) tan 89^(@) + sec (90^(@) - theta). cosec theta - tan (90^(@) - theta ) cot theta

Show that: sin (40^(@) + theta) cos (10^(@) + theta) -cos(40^(@) + theta) sin (10^(@) + theta) = (1)/(2)

Prove that, sin(40^(@)+theta)cos(10^(@)+theta)-cos(40^(@)+theta)sin(10^(@)+theta)=(1)/(2)

The value of {cos(40^(@)+theta)-sin(50^(@)-theta)} is

Without using trigonometric tables,evaluate each of the following: (sin^(2)20^(@)+sin^(2)70^(@))/(cos^(2)20^(0)+cos^(2)70^(@))+(sin(90^(@)-theta)sin theta)/(tan theta)+(cos(90^(@)-theta)cos theta)/(cot theta)+cos(40^(0)+theta)-sin(50^(@)-theta)+(cos^(2)40^(0)+cos^(2)50^(@))/(sin^(2)40^(0)+sin^(2)50^(@))

Solve cos(50^(@)+ theta) = sin (30^(@)+theta) .

Prove that (i) " sin " (50^(@) + theta ) " cos " (20^(@) + theta) - " cos " (50^(@) + theta) " sin " (20^(@) + theta) =(1)/(2) (ii) " cos " (70^(@) + theta ) " cos " (10^(@) + theta ) + " sin " (70^(@) + theta) " sin " (10^(@) + theta)=(1)/(2)