" 9."(dy)/(dx)=(y(2y-x))/(x(2y+x));" given "y=1," when "x=1quad " [CBSE "'08

(dy)/(dx)=(y(2y-x))/(x(2y+x))=0 , given y=1, when x=1

Find the particular solution of the differential equation (dy)/(dx)=(y(2y-x))/(x(2y+x)) ,given that y=1 when x=1 .

(dy)/(dx)=(y^(2)+y+1)/(x^(2)+x+1)

(dy)/(dx)=(y^(2)-y+1)/(x^(2)-x+1)

x(dy)/(dx)=y+xtan""(y)/(x),"given "y=(pi)/(2), when x=1

(dy)/(dx)=(x+y+1)/(x+y-1) , given y=1, when x=1

(dy)/(dx)=(x+y+1)/(x+y-1) given y=1 when x=1

Solve the following differential equation: (dy)/(dx)=(x(2y-x))/(x(2y+x)), if y=1 when x=1

(dy)/(dx)=1+e^(2x-y) , given y=2, when x=2

(dy)/(dx)=(x+y+1)/(2x+2y+3)