44.quad i5n^(2)-n-28

(i) .^(n)C_(7)=.^(n)C_(5) , find n. (ii) If.^(n)C_(14)=.^(n)C_(16) , find .^(n)C_(28) .

Let I_(n)=int(x^(n))/(sqrt(x^(2)+2x+5))dx then I_(n)=(x^(m-1))/(n)sqrt(x^(2)+2x+5)-lambda I_(n-1)-mu I_(n-2) where lambda,mu and m' are involving n' then

If n(ne 1) in N and I_(n) =int sec^(n)x dx then (n-1) I_(n)-(n-2)I_(n-2) =

" *.i).i) If "n" is an integer then show that "(1+i)^(2n)+(1-i)^(2n)=2^(n+1)cos(n pi)/(2)

The value of i^(2n)+i^(2n+1)+i^(2n+2)+i^(2n+3), where i=sqrt(-1), is

Find the value of i^n+i^(n-1)+i^(n-2)+i^(n-3) for all n in Ndot

If I_(n)=int(a^(2)+x^(2))^((n)/(2))dx, then show that I_(n)=((x(a^(2)+x^(2))^((n)/(2)))/(n+1))+(na^(2))/(n+1)I(n-2)

If n in N and I_(n) = intsin^(n) x dx then nI_(n)-(n-1)I_(n-2) =

If I_(n) = int_0^(pi/2) sin^(n)x dx then I_(n)/(I_(n-2)) =