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|(2,3,2,1),(1,3,2,1),(1,2,2,1),(1,0,1,1)...

`|(2,3,2,1),(1,3,2,1),(1,2,2,1),(1,0,1,1)|`

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If A= [(2,1,2),(1,2,0),(2,1,-1)] ,B= [(1,1,0),(2,2,1),(1,0,-1)] Verify the following (III) (3A)^(T)=3A^(T)

If A=[(2,3,1),(0,-1,5)],B=[(1,2,-1),(0,-1,3)] then 2A-3B=

If A=[(1,2,3),(-1,0,2),(1,-8,-1)],B=[(4,5,6),(-1,0,1),(2,1,2)],C=[(-1,-2,1),(-1,2,3),(-1,-2,2)] , find (i) 2B-3C (ii) A-2B+3C .

Show that (i) [(5,-1),(6,7)][(2,1),(3,4)]!=[(2,1),(3,4)][(5,-1),(6,7)] (ii) [(1,2,3),(0,1,0),(1,1,1)][(-1,1,0),(0,-1,1),(2,3,4)]!=[(-1,1,0),(0,-1,1),(2,3,4)][(1,2,3),(0,1,0),(1,1,0)] .

If A=[(3,1,2),(1,2,3)] ,B= [(1,0),(2,1),(1,1)] find AB and BA.

Show that (i) [(5,-1),(6,7)][(2,1),(3,4)] ne [(2,1),(3,4)][(5,-1),(6,7)] (ii) [(1,2,3),(0,1,0),(1,1,0)][(-1,1,0),(0,-1,1),(2,3,4)] ne [(-1,1,0),(0,-1,1),(2,3,4)][(1,2,3),(0,1,0),(1,1,0)]

Show that (i) [(5,-1),(6,7)][(2,1),(3,4)] ne [(2,1),(3,4)][(5,-1),(6,7)] (ii) [(1,2,3),(0,1,0),(1,1,0)][(-1,1,0),(0,-1,1),(2,3,4)] ne [(-1,1,0),(0,-1,1),(2,3,4)][(1,2,3),(0,1,0),(1,1,0)]