यदि `theta` एक न्यूनकोण है और `tan(4theta-50^(@))=cot(50^(@)-theta)` है तो `theta` का मान ज्ञात डिग्री में क्या होगा?

Options

A. 30
B. 40
C. 50
D. 20

Answer

a

Explanation

We know that
`tan (90^(@)-theta)=cot theta`
and `cot(90^(@)-theta)=tan theta`
`rArrcot(90^(@)-(4theta-50^(@))=cot(50^(@)-theta)`
`rArr90^(@)-(4theta-50^(@))=50^(@)-theta`
`rArr90^(@)-4theta+50^(@)=50^(@)-theta`
`rArr90^(@)=3theta`
then `theta=30^(@)`