यदि `costheta+sectheta=2`, तो `cos^(6)theta+sec^(6)theta` का मान ज्ञात करे?

Options

A. 4
B. 8
C. 1
D. 2

Answer

d

Explanation

`cos theta+sec theta=2`
put `theta=0^(@)`
`cos0^(@)+sec0^(@)=2`
`rArr1+2=2rArr2=2`
(matched, so `theta=0^(@)`)
`= cos^(2)theta+sec^(6)theta`
`=(1)^(6)+(1)^(6)= 1+1=1`
Alternate
if `x+(1)/(x)=2`
then x=1
So, `cos theta+sec theta`
Hense, `cos theta=1`
we have to find the value of `cos^(6)+sec^(6)theta`
`rArrcos^(4)theta+(1)/(cos^(6)theta)`
`rArr1+1=2`