Find value of the following `3(sin^(4)theta+cos^(4)theta)+2sin^(6)theta+cos^(6)theta)+12sin^(2)thetacos^(2)theta` :

Options

A. 3
B. 2
C. 0
D. 5

Answer

d

Explanation

The value of `3sin^(2)theta+cos^(4)theta)+2`
`(sin^(6)theta+cos^(6)theta)+12sin^(2)thetacos^(2)theta`
Using `theta=0^(@)`
`because sin0^(@)=0^(@)`
`cos0^(@)=0^(@)`
`cos 0^(@)=1`
`rArr3(0+1^(4))+2(0+1^(6))+1.2xx0xx1`
`rArr1+2=5`