If `xcostheta-sintheta=1," then "x^(2)-(1+x^(2))sintheta` equals

Options

A. 1
B. -1
C. 0
D. 2

Answer

a

Explanation

Given let x=1 and `theta=0^(@)`
`rArrx cos theta-sintheta+1`..........(i)
`rArr1xx1-(0)=1`
`rArr1=1`
putting value `x=1` and `theta=0^(@)` in following equation
`rArrx^(2)-(1+x^(2))sintheta`
`rArr1^(2)-(1+1^(2))xx sin0^(@)`
=1