If `theta` be acute angle and `cos theta=(15)/(17)`
then the angle of`cos(90^(@)-theta)` (यदि न्यूनकोण है और `cos theta=(15)/(17)` तो `cos(90^(@)-theta)` का मान ज्ञात करे )

Options

A. `(2sqrt8)/(15)`
B. `(8)/(15)`
C. `(sqrt2)/(15)`
D. `(sqrt2)/(17)`

Answer

b

Explanation

`cos theta=(15rarr"Base")/(17rarr"Hypo.")`

perpendicular=8
`=cot[90^(@)-theta)=tan theta=(8)/(15)`
`[therefore tan theta=(P)/(B)]`