In `triangleABC, ltB=90^(@) and AB:BC=BC=2:1` Then value of (SinA+CotC)(है तो (SinA+CotC) का मान ज्ञात करे )

Options

A. `3+sqrt5`
B. `(2+sqrt5)/(2sqrt5)`
C. `2sqrt5`
D. `3+sqrt5`

Answer

b

Explanation

`AC=sqrt(2^(2)+1^(4))=sqrt(5)`
`sinA+cotC`
`(BC)/(AC)+(BC)/(AB)`
`(1)/sqrt(5)+(1)/(2)rArr(2+sqrt(5))/(2sqrt(5))`