यदि `sin theta + "co s ec" = 2 ` हो, तो `sin^(n) theta+ "co s ec"^(n) theta ` का मान क्या होगा ?

Options

A. `2^(n)`
B. `2^((1)/(n))`
C. 2
D. 0

Answer

c

Explanation

`sin theta+co s ectheta=2`
`sin theta+(1)/(sin theta)=2`
`x+ (1)/(x)=2` then `x=1` this is the same type of expression So,
` sin theta=1`
`& co s ectheta=1`
`sin^(2)theta+co s ec^(6)theta=(1)^(n)+(1)^(n)=2`