`cot17^(@)(cot73^(@)cos^(2)22^(@)+(1)/(Cot17^(@)Sec^(2)68^(@)))` का मान क्या है ?

Options

A. 0
B. 1
C. 27
D. `sqrt(3)`

Answer

b

Explanation

`rArrcot17^(@)(cot73^(@)cos^(2)22^(@))+(1)/(cot17^(@)sec68^(@))`
`=cot17^(@)[ cot(90-17^(@))cos^(2)(90-60)+(tan17^(@)cos^(2)68)`
`=cot17^(@)(tan17^(@)cos^(2)68)`
`=cot17^(@)(sin^(2)68+cos^(2)68)`
=1(1)=1