यदि एक त्रिभुज ABC में `sinA=cosB` हो, तो `cosC` का मान कितना है ?

Options

A. `(sqrt(3))/(2)`
B. 0
C. 1
D. `(1)/(sqrt(2))`

Answer

b

Explanation

In `Delta,angleA+angleB+angleC`
`=180^(@)` .......(i)
`sinA=cosB`
`sinA=sin(90-B)`
`A=90^(@)-B`
`A+B=90^(@)` ........(ii)
from equation (i) and (ii)
`angleC=90^(@)`
So, `cosC=c os90^(@)=0`