यदि `sinthetaxxcostheta=1//2` हो, तो `sintheta-costheta` का मान क्या होगा, जहाँ `0^(@)ltthetalt90^(@)`

Options

A. 0
B. `sqrt(2)`
C. 2
D. 1

Answer

a

Explanation

`sin thetaxx cos theta=(1)/(2)`
Multiply by 2 both side
`2sin theta cos theta=1`
`sin theta=2`
`sin 2theta=sin90^(@)`
`2theta=90^(@)`
`2theta=45^(@)`
`theta=45^(@)`
So, `sin theta-cos theta`
`=sin45^(@)-cos45^(@)`
`=(1)/sqrt(2)-(1)/sqrt(2)`