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The gravitational field due to a mass di...

The gravitational field due to a mass distribution is `E=(A)/(x^(2))` in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x is

A

`(2A)/(x)`

B

`(2A)/(x^(3))`

C

`(A)/(x)`

D

`(A)/(2x^(2))`

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The correct Answer is:
C
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