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The gravitational force acting on a part...

The gravitational force acting on a particle, due to a solid sphere of uniform density and radius `R`, at a distance of `3R` from the centre of the sphere is `F_1.` A spherical hole of radius `(R//2)` is now made in the sphere as shown in diagram. The sphere with hole now exerts a force `F_2` on the same particle. ratio of `F_1` to `F_2` is

A

`(9)/(50)`

B

`(41)/(50)`

C

`(3)/(25)`

D

`(22)/(25)`

Text Solution

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The correct Answer is:
B
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