If `2 cos theta + sin theta =1(theta != pi/2)` then `7 cos theta + 6 sin theta` is equal to

Statement I If 2 cos theta + sin theta=1(theta != (pi)/(2)) then the value of 7 cos theta + 6 sin theta is 2. Statement II If cos 2theta-sin theta=1/2, 0 lt theta lt pi/2 , then sin theta+cos 6 theta = 0 .

Statement I If 2 cos theta + sin theta=1(theta != (pi)/(2)) then the value of 7 cos theta + 6 sin theta is 2. Statement II If cos 2theta-sin theta=1/2, 0 lt theta lt pi/2 , then sin theta+cos 6 theta = 0 .

If 2cos theta+sin theta=1(theta!=(pi)/(2)) then 7cos theta+6sin theta is equal to

If 2 cos theta + sin theta =1 then 7 cos theta + 6 sin theta is equal to

If sin theta cos theta = 1//2, then what is sin^6 theta +cos^6 theta equal to?

If sin theta + 2 cos theta = 1, where 0 lt theta lt (pi)/(2), then what is 2 sin theta - cos theta equal to ?

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

If sin theta + 2cos theta = -1 , where 0 lt theta lt pi/2 , what is 2 sin theta - cos theta equal to ?