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In the figures shown current in the long...

In the figures shown current in the long straight wire varies as `I=I_(0)((t_(0)-t)/(t_(0))` where `I_(0)` is the initial current The charge flown through resistance in the time `t_(0)` is

A

`(mu_(0))/(2pi)(lbl_(0))/(R)`

B

`(mu_(0))/(2pi)(ll_(0))/(R)In((b)/(a))`

C

`(mu_(0))/(2pi)(ll_(0))/(R)In((a+b)/(a))`

D

`(mu_(0))/(2pi)(al_(0))/(R)In((b)/(l))`

Text Solution

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The correct Answer is:
C
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