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In the given circuit, the AC source has ...

In the given circuit, the AC source has `omega=50 rad//s`. Considering the inductor and capacitor to be ideal, the correct choice (s) is (are):

A

The voltage across `100Omega` resistor `20sqrt2V`

B

The voltage across `50Omega` resistor `20sqrt2V`

C

The curren through the circuit,`(2)/(sqrt10)A`

D

The current through the circuit, l is 1.2A

Text Solution

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The correct Answer is:
A, B, C
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Knowledge Check

  • In the given circuit, the AC source has omega = 100 rad/s. Considering the inductor and capacitor to be ideal, the correct choice(s) is (are)

    A
    The current through the circuit, I is 0.3 A.
    B
    The current thorgh the circuit, I is 0.3 `sqrt(2)A`.
    C
    The voltage across `100 Omega` resistor `=10sqrt(2)V`
    D
    The voltage across `50Omega` resistor = 10 V.

  • In the given circuit, then AC source has omega=50 rad//s Considering the indcutor and capacitor and capacitor to be ideal, the correct choice(s) is (are):

    A
    The voltage across `100Omega` resistor `20sqrt2V`
    B
    The voltage across `50Omega` resistor `20sqrt2V`
    C
    The current through the circuit, l is `(2)/(sqrt10)A`
    D
    The current through the circuit, l is 1.2A

  • The value of impedance in parallel LC circuit at resonance is (assuming inductor and capacitor to be ideal)

    A
    minimum
    B
    maximum current
    C
    infinite
    D
    zero

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    A student in a lab took a coil and connected it to a 12 VDC source. He measures the steady state current in the circuit to be 4 A . He then replaced the 12 VDC source by a 12V,(omega=50rad//s)AC source and observes that the reading in the AC ammeter is 2.4 A . He then decides to connect a 2500 muF capacitor in series with the coil and calculate the average power developed in the circuit. Further he also decides to study the variation in current in the circuit (with the capacitor and the battery in series). The value of resistance of the coil calculated by the student is

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