Home
Class 12
PHYSICS
In the circuit diagram shown in Figure E...

In the circuit diagram shown in Figure E=18V , L=2H, `R_(1)=3Omega , R_(2)=6Omega`. Switch S is closed at t=0 Match the following:

Text Solution

Verified by Experts

The correct Answer is:
(A) R, (B) P, (C) Q, (D) Q
Promotional Banner

Similar Questions

Explore conceptually related problems

In the circuit shown in figure, E = 120 V, R_1 = 30.0Omega, R_2 = 50.0 Omega and L=0.200H . Switch S is closed at t = 0 . Just after the switch is closed. (a) What is the potential difference V_(ab) across the inductor R_1 ? (b) Which point, a or b , is at higher potential? (c) What is the potential difference V_(cd) across the inductor L ? (d) Which point, c or d , is at a higher potential? The switch is left closed for a long time and then is opened. Just after the switch is opened (e) What is the potential difference V_(ab) across the resistor R_1 ? (f) Which point a or b, is at a higher potential? (g) What is the potential difference V_(cd) across the inductor L ? (h) Which point, c or d , is at a higher potential?

In the circuit shown in figure, E = 10 V, r = 1Omega , R = 4Omega and L = 5H. The circuit is closed at time t = 0. Then, match the following two columns. {:(,"Column I",,"Column II"),(A.,V_(AD)" at t = 0",p,4 V),(B.,V_(BC)" at t = 0",q,8 V),(C.,V_(AB)" at t ="oo,r.,0V),(D.,V_(AD)" at t"=oo,s.,10V):}

In the circuit shown in figure L=10H, R=5Omega, E=15V. The switch S is closed at t=0 . At t=2s the current in the circuit is

In the circuit shows in Fig E = 15 V , R_(1) = 1Omega , R_(2) = 1 Omega , R_(3) = 2Omega , and L = 1.5 H . The currents flowing through R_(1),R_(2) ,and R_(3) are i_(1),i_(2) , and i_(3) , respectively. Immediately after connecting switch S ,

In the circuit shows in Fig E = 15 V , R_(1) = 1Omega , R_(2) = 1 Omega , R_(3) = 2Omega , and L = 1.5 H . The currents flowing through R_(1),R_(2) ,and R_(3) are i_(1),i_(2) , and i_(3) , respectively. Immediately after tuning switch S on,

In the circuit shows in Fig. , E = 10 V , R_(1) = 5 Omega , R_(2) = 10 Omega , and L = 5 H . For the two separate conditions, (i) switch S is just closed and (ii) switch S is closed for a long time, calculate a. current i_(1) through R_(1) , b. current i_(2) through R_(2) , c. current i through the switchs, d. the potential difference across R_(2) , e. the potential difference across L , f. di_(2)//dt .

In the circuit diagram shown in figure match the following two columns when switch S is closed.

In the circuit shown in the figure, E = 50.0 V, R = 250 Omega and C = 0.500 muF. The switch S is closed for a long time, and no voltage is measured across the capacitor. After the switch is opened, the voltage across the capacitor reaches a maximum value of 150 V . What is the inductance L ?