In L-C-R series circuit suppose omega(r)...

In L-C-R series circuit suppose `omega_(r)` is resonance frequency, then match the following table,
`{:(,,"Table-1",,"Table-2"),(,(A),"If " omegagtomega_(r),(P),"Current will lead the voltage"),(,(B),"If " omega=omega_(r),(Q),"Voltage will lead the current"),(,(C),"If " omega=2omega_(r),(R),X_(L)=2X_(C)),(,(D),"If " omegaltomega_(r),(S),"Current and voltage are in phase"),(,,,(T),"None"):}`

Verified by Experts

The correct Answer is:

(A) Q, (B) S, (C) Q, (D) P

Similar Questions

Explore conceptually related problems

Angular frequency omega in an AC, L-C-R series circuit is gradually increased. Then, match the following two columns.

In an L-C-R series circuit R = 10Omega, X_(L) = 8Omega and X_(C) = 6Omega the total impedance of the circuit is -

In a series L-C-R circuit X_(L)350 Omega, X_(C)=200 Omega and R = 150 Omega .

In a given series LCR circuit R=4Omega, X_(L)=5Omega and X_(C)=8Omega , the current

In R-L-C series circuit, we have same current at angular frequencies omega_(1) and omega_(2) . The resonant frequency of circuit is

In an L C R circuit having L = 8 H, C = 0 5muF and R=100Omega in series, the resonance frequency in rad/s is

Prove that (p+q omega+r omega^(2))/(r+p omega+q omega^(2))=omega^(2)

If Z= sqrt(R^(2)+(X_(C)-X_(L))^(2)) then give the phase relationship of current and voltage.

In a series LCR circuit, resistance R=10Omega and the impedence Z=20Omega the phase difference between the current and the voltage is