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If cosalpha+cosbeta=0=sinalpha+sinbeta, ...

If `cosalpha+cosbeta=0=sinalpha+sinbeta,` then `cos2alpha+cos2beta` is equal to (a)`-2"sin"(alpha+beta)` (b) `-2cos(alpha+beta)` (c)`2"sin"(alpha+beta)` (d) `2"cos"(alpha+beta)`

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Knowledge Check

  • If cos alpha+cos beta=0=sin alpha+sinbeta, then cos2alpha+cos 2beta=

    A
    `-2sin(alpha+beta)`
    B
    `-2cos (alpha+beta)`
    C
    `2sin(alpha+beta)`
    D
    `2cos (alpha+beta)`
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