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If 3sinbeta=sin(2alpha+beta) then tan(a...

If `3sinbeta=sin(2alpha+beta)` then `tan(alpha+beta)-2tanalpha` is (a)independent of `alpha` (b)independent of `beta` (c)dependent of both `alpha` and `beta` (d)independent of both `alpha` and `beta`

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To solve the problem, we start with the given equation: \[ 3 \sin \beta = \sin(2\alpha + \beta) \] We need to find the expression for: \[ \tan(\alpha + \beta) - 2 \tan \alpha \] ...
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