" (f) "16(2x-1)^(2)-25z^(2)

Factorize each of the following algebraic expressions: 16(2x-1)^(2)-25z^(2)4a^(2)-9b^(2)-2a-3b

Fractorise: (3x-4y)^(2) - 25z ^(2)

If P(x , y) ,F_(1) (3,0) , F_(2) (-3, 0) " and " 16x^(2) + 25 y^(2) = 400 then show that PF_(1)+PF_(2)=10

Factorize: 16a^(2)-(25)/(4a^(2))( ii) 16a^(2)b-(b)/(16a^(2))100(x+y)^(2)-81(a+b)^(2)(x-1)^(2)-(x-2)^(2)

If (x-3)^(2) + (y-5)^(2) + (z-4)^(2) = 0, then the value of (x^2)/(9) + (y^2)/(25) + (z^2)/(16) is

The equation of the ellipse having a vertex at (6,1) a focus at (4,1) and the eccentricity (3)/(5) is 1) ((x-1)^(2))/(16)+((y-1)^(2))/(25)=1 (2) ((x-1)^(2))/(25)+((y-1)^(2))/(16)=1 3) ((x+1)^(2))/(25)+((y+1)^(2))/(16)=1 (4) ((x+1)^(2))/(16)+((y+1)^(2))/(25)=1

If a^(2)+b^(2)+c^(2)=16,x^(2)+y^(2)+z^(2)=25 and ax+by+cz=20 then the value of (a+b+c)/(x+y+z)

Factories 25 x ^(2) + 16 y ^(2) + 4z ^(2) - 40 xy + 16 xy - 20xy

Find the product: (3x-4y+5z)(9x^(2)+16y^(2)+25z^(2)+12xy-15zx+20yz)

If P=(x, y), F_(1)=(3,0), F_(2)=(-3,0) and 16 x^(2)+25 y^(2)=400 then P F_(1)+P F_(2)=