sin20^(@)*sin40^(@)*sin60^(@)*sin80^(@)=(1)/(16)

Prove that: sin20^(@)sin40^(0)sin60^(@)sin80^(@)=(3)/(16)

For A in R , prove that sin20^(@)sin40^(@)sin60^(@)sin80^(@)=3/16

Prove that: sin20^(0)sin40^(0)sin60^(@)sin80^(@)=(3)/(16)

sin20^(@)+sin40^(@)-sin80^(@)=

Prove that: i) sin20^(@)sin40^(@)sin60^(@)sin80^(@)=3/16 ii) sin10^(@)sin50^(@)sin60^(@)sin70^(@)=sqrt(3)/16 iii) sin20^(@)sin40^(@)sin80^(@)=sqrt(3)/8

Prove that: i) sin20^(@)sin40^(@)sin60^(@)sin80^(@)=3/16 ii) sin10^(@)sin50^(@)sin60^(@)sin70^(@)=sqrt(3)/16 iii) sin20^(@)sin40^(@)sin80^(@)=sqrt(3)/8

sin20^(0)sin40^(0)sin60^(0)sin80^(@)=(3)/(16)

Find sin20^(@)sin40^(@)sin60^(@)sin80^(@) .

sin 20^(@) sin 40^(@) sin 60^(@) sin 80^(@) =(3)/(16)

Prove that sinthetasin(60^(@)+theta)sin(60^(@)-theta)=1/4sin3theta Hence deduce that sin20^(@)sin40^(@)sin60^(@)sin80^(@)=3//16 (OCT-97,INST.93)