sec^(3)(1^(2))/(-2)

sec^(3)(x^(2)+1)

If tanA=ntanBandsinA=msinB then sec^(3)A((m^(2)-1)/(n^(2)-1))^((3)/(2) =?

sec^(-1)((2)/(3)) + cosec^(-1) ((2)/(3)) = ……….

In Delta ABC , show that: (r_(1)+r_(2)) sec^(2) ""(C)/(2) = (r_(2) +r_(3)) sec^(2) ""(A)/(2) =(r_(3)+r_(1)) sec^(2)""(B)/(2)

The value of alpha^(3)/2cosec^(2)(1/2tan^(-1)""alpha/beta)+beta^(3)/2sec^(2)(1/2tan^(-1)(beta/alpha)) is equal to

lim_(n rarr oo)[(1)/(n^(2))sec^(2)((pi)/(3n^(2)))+(2)/(n^(2))sec^ (2)((4 pi)/(3n^(2)))+(3)/(n^(2))sec^(2)((9 pi)/(3n^(2)))+. .....+(1)/(n)sec^(2)((pi)/(3))]

sec^(2)(tan^(-1)2) +"cosec"^(2)(cot^(-1)3)=