100=5^(b)

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boiling point of solution was found to be 100.5^(@) C. K_(b) for H_(2)O is :

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boiling point of solution was found to be 100.5^(@) C. K_(b) for H_(2)O is :

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boiling point of solution was found to be 100.5^(@) C. K_(b) for H_(2)O is :

When 1 mole of a solute is dissolved in 1 kg of H_(2)O , boilling point of solution was found to be 100.5^(0)C . K_(b) for H_(2)O is

Write each of the following as decimals. (a) 20 +9 + 4/(10) + 1/(100) (b) 137 + 5/ (100) (c) 7/(10) + 6/100 + 4/(1000) (d) 23 + 2/(10) + 6/(1000) (e) 700 +20 + 5+9/(100)

Write each of the following as decimals.(a) 20+9+(4)/(10)+(1)/(100) (b) 137+5(100)(c)(7)/(10)+(6)/(100)+(4)/(1000)(d)23+(2)/(10)+(6)/(1000) (e) 700+20+(5)(9)/(100)11

If (1.5)^(a)=(0.15)^(b)=100 then (1)/(a)-(1)/(b) equals to

A=cos20^(@) - sin 20^(@) ,B=cos100^(@) + sin100^(@) , C= cos""(5pi)/6+ sin""(2pi)/3 then the ascending order is

At 100^(@)C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If k_(b) = 0.5 , the boiling point of this solution will be -