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" 10."25x(x+1)=-4...

" 10."25x(x+1)=-4

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Solve by factorization: 25x(x+1)=-4

Solve by factorization: 25 x(x+1)=-4

Find the nature of the roots of the following quadratic equations. If the real roots exist, find them :- 25x(x+1)=-4 .

If 5x - (1)/(2x) = 3 , then find 25x^(2) + (1)/(4x^(2)) .

Reduce the given Rational expression to its lowest form (10x^(3)-25x^(2)+4x-10)/(-4-10x^(2)) .

int _ (- (pi) / (2)) ^ ((pi) / (2)) sin ^ (10) x (6x ^ (9) -25x ^ (7) + 4x ^ (3) -2x) dx =

If 5x +1/(3x)=4 , then what is the value of 9x^2+1/(25x^2) ? यदि 5x +1/(3x)=4 है, तो 9x^2+1/(25x^2) का मान क्या होगा ?

If f(x) =tan^(-1)((x)/(1+20x^(2))) , show that, f'(x)=(5)/(1+25x^(2))-(4)/(1+16x^(2))