|[2cos theta,1,0],[1,2cos theta,1],[0,1,2cos theta]|=(sin4 theta)/(sin theta)-(2tan alpha)tan t

(1-sin theta)/(cos theta)-(cos theta)/(1+sin theta)=2tan theta

Prove that: (sin2 theta)/(1+cos2 theta)=tan theta

Prove that: (sin2 theta)/(1+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

The value of sec theta((1+ sin theta)/(cos theta) + (cos theta)/(1+sin theta))- 2 tan^2 theta is

(1)/(1-sin theta)-(1)/(1+sin theta)=(2tan theta)/(cos theta)

If (a cos theta_(1),a sin theta_(1)),(a cos theta_(2),a sin theta_(2)) and (a cos theta_(3),a sin theta_(3)) represent the vertices of an equilateral triangle inscribed in a circle,then (a)cos theta_(1)+cos theta_(2)+cos theta_(3)=0 (b) sin theta_(1)+sin theta_(2)+sin theta_(3)=0(c)tan theta_(1)+tan theta_(2)+tan theta_(3)=0(d)cot theta_(1)+cot theta_(2)+cot theta_(3)=0

cos theta(tan theta+2)(2tan theta+1)=2sec theta+5sin theta