If `OA and OB` are two perpendicular chords of the circle `r = a cos theta + b sin theta` epassing through origin, then the locus of the mid point of `AB` is :

The locus of the point x=a cos theta, y=b sin theta is

The locus of the point x=a+b cos theta y=b+a sin theta is

The locus of the point (a cos h theta, b sin h theta ) is

OA and OB are two perpendicular straight lines. A straight line AB is drawn in such a manner that OA+OB=8 . Find the locus of the mid point of AB.

OA and OB are two perpendicular straight lines. A straight line AB is drawn in such a manner that OA+OB=8 . Find the locus of the mid point of AB.

OA and OB are two perpendicular straight lines. A straight line AB is drawn in such a manner that OA+OB=8 . Find the locus of the mid point of AB.

OA and OB are two perpendicular straight lines. A straight line AB is drawn in such a manner that OA+OB=8 . Find the locus of the mid point of AB.

If OA and OB are two equal chords of the circle x^(2)+y^(2)-2x+4y=0 perpendicular to each other and passing through the origin,the slopes of OA and OB are the roots of the equations

The locus of the point ( a cos theta + b sin theta, a sin theta - b cos theta ) where 0 le theta lt 2pi is