If `|x^(2)-x|=2` then x is

Solve the following : (i) |x-2|=(x-2) " (ii) " |x+3| = -x-3 (iii) |x^(2)-x|=x^(2)-x " (iv) " |x^(2)-x-2| =2+x-x^(2)

If |x^2-2x+2|-|2x^2-5x+2|=|x^2-3x| then the set of values of x is

| x ^ (2) + x + 2 |-| x ^ (2) -x + 1 | = | 2x + 1 |

Solve the following (i) | x-2 | = (x-2) (ii) |x+3 |=-x-3 (iii) |x^2-x|=x^2-x (iv) |x^2-x-2|=2 +x-x^2

If (x^(2)-2|x|)(|2x|-2)-9((2|x|-2)/(x^(2)-2|x|)) le0 then