The equation of the hyperbola whose centre is (6,2) one focus is (4,2) and of eccentricity 2 is `3(x-6)^2-(y-2)^2=3` b. `(x-6)^2-3(y-2)^2=1` c. `(x-6)^2-2(y-2)^2=1` d. `2(x-6)^2-(y-2)^2=1`

The equation of the hyperbola whose centre is (6,2) one focus is (4,2) and of eccentricity 2 is (A) 3(x-6)^(2)-(y-2)^(2)=3(B)(x-6)^(2)-3(y-2)^(2)=1(C)(x-6)^(2)-2(y-2)^(2)=1(D)2(x-6)^(2)-(y-2)^(2)=1

Find the equation of the hyperbola whose directrix is 2x+y=1, focus (1,2) and eccentricity sqrt(3).

Find the equation of the hyperbola whose diretrix is 2x+y=1, focus (1, 2) and eccentricity sqrt(3) .

Find the equation of the hyperbola whose : focus is (2,-1) directrix is 2x+3y=1 and eccentricity =2

The equation of the hyperbola whose focus is (1,2) , directrix is the line x+y+1=0 and eccentricity 3//2 , is

Find the equation of the ellipse whose : One focus is (6, 7) , directrix is x + y + 2 and eccentricity is 1/sqrt(3)

The equation of the ellipse with its centre at (1, 2), focus at (6, 2) and passing through the point (4 ,6) is (x-1)^(2)/a^(2)+(y-2)^(2)/b^(2)=1, then

Write the centre and eccentricity of the ellipse 3x^(2)+4y^(2)-6x+8y-5=0

The locus of the foot of perpendicular drawn from the centre of the ellipse x^2+""3y^2=""6 on any tangent to it is (1) (x^2-y^2)^2=""6x^2+""2y^2 (2) (x^2-y^2)^2=""6x^2-2y^2 (3) (x^2+y^2)^2=""6x^2+""2y^2 (4) (x^2+y^2)^2=""6x^2-2y^2

The equation of the circle passing through the foci of the ellipse (x^2)/(16)+(y^2)/9=1 , and having centre at (0, 3) is (1) x^2+y^2-6y+7=0 (2) x^2+y^2-6y-5=0 (3) x^2+y^2-6y+5=0 (4) x^2+y^2-6y-7=0