If `costheta_1 =2costheta_2,` then `tan((theta_1-theta_2)/2)tan((theta_1+theta_2)/2)` is equal to (a)`1/3` (b) `-1/3` (c)`1` (d) `-1`

int(1-costheta)^2 d theta is equal to

If : cos theta_(1) = 2 * cos theta_(2), ltbr gt "then" (tan""(theta_(1)-theta_(2))/(2))(tan""(theta_(1) + theta_(2))/(2))= A) (1)/(3) B) -(1)/(3) C)1 D)-1

int(costheta-cos2theta)/(1-cos theta)d theta=

If theta=60^(@) , then (1+tan^(2)theta)/(2tan theta) is equal to

If sin theta_1 + sin theta_2 + sintheta_3 =3 then cos theta_1 + cos theta_2 + costheta_3 is equal to

(tan^(2)(2 theta)-tan^(2)theta)/(1-tan^(2)(2 theta)tan^(2)theta) is equal to-

What is ((1 + sec theta-tan theta)costheta)/((1+sec theta+tan theta)(1 -sintheta)) equal to ?