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" 2"quad (x+" tany ")dy=sin2ydx...

" 2"quad (x+" tany ")dy=sin2ydx

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Solve the following differential equations: (x+tany)dy=sin2ydx

Solve the following differential equations: (x+tan y)dy=sin2ydx

Solve: (x+tany)dy = sin 2y dx.

Solution of the differential equation tany (dy)/(dx)=sin(x+y)+sin(x-y) is -

Solve (dx)/x = tany dy

Statement-1: Solution of the differential equation tany *dy/dx =sin(x+y)+sin(x-y) is secy+2cosx=c .Statement-2: The differential equation tany *dy/dx =sin(x+y)+sin(x-y) is homogenous (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true

Find integrating factor of (x+tany) dy = tan ydx

The solution of the differential equation (dy)/(dx) - (tany)/x = (tan y sin y)/(x^(2)) is