In triangle `A B C ,a , b , c` are the lengths of its sides and `A , B ,C` are the angles of triangle `A B Cdot` The correct relation is given by (a)`(b-c)sin((B-C)/2)=acosA/2` (b) `(b-c)cos(A/2)=as in(B-C)/2` (c)`(b+c)sin((B+C)/2)=acosA/2` (d)`(b-c)cos(A/2)=2asin(B+C)/2`

If a ,b ,c denote the lengths of the sides of a triangle opposite to angles A ,B ,C respectively of a A B C , then the correct relation among a ,b , cA ,Ba n dC is given by (b+c)sin((B+C)/2)=acos b. (b-c)cos(A/2)=asin((B-C)/2) c. (b-c)cos(A/2)=2asin((B-C)/2) d. (b-c)sin((B-C)/2)="a c o s"A/2

If a,b,c are sides opposte to the angles A,B , C then which of the following is correct (1)(b+c)cos((A)/(2))=a sin((B+C)/(2))(2)(b+c)cos((B+C)/(2))=a sin((A)/(2))(3)(b-c)cos((B-C)/(2))=a(cos A)/(2)(4)(b-c)cos((A)/(2))=a sin((B-C)/(2))

If A,B,C are the angles of a triangle then prove that cos A+cos B-cos C=-1+4cos((A)/(2))cos((B)/(2))sin((C)/(2))

If A,B,C are the interior angles of a triangle ABC, prove that tan((C+A)/(2))=(cot B)/(2)( ii) sin((B+C)/(2))=(cos A)/(2)

Which of the following is true in a triangle ABC?(1)(b+c)sin((B_(C))/(2))=2a cos((A)/(2))(2+c)cos((A)/(2))=2a sin((B-C)/(2))

If A,B,C are the angles of a triangle ABC that cos((3A+2B+C)/(2))+cos((A-C)/(2))=

If A ,B, C are the angles of a triangle , then : tan""(A)/(2) * tan""(B+C)/(2) +cos""(A+B)/(2) *csc""(C)/(2)=

Let a, b, c be the sides of a triangle and let A, B, C be the respective angles. If b+c=3a, then find the value of the ratio cos((B-C)/2)/cos((B+C)/2)

If in triangle ABC, a, c and angle A are given and c sin A lt a lt c , then ( b_(1) and b_(2) are values of b)