" (i) "1+6+11+16+...+x=148

Solve: (Find x) 1 + 6+ 11+ 16+ ….+x= 148

Consider the equation 1+6+11 + 16 + ... +x= 148 Prove that x^2+5x-1476=0

Consider the equation 1+6+11 + 16 + ... +x= 148 Solve the given equation

Consider the equation 1+6+11 + 16 + ... +x= 148 If n is the number of terms in the sum, prove that n=(x+4)/5 -

Solve the equation : 1+6+11+ 16+.....+x= 148

solve: 1+6+11+16+.......+x=148

solve: 1 + 6 + 11 + 16 +.........+ x = 148

Find last term of an A.P. whose sum is 148 and A.P. is 1,6, 11, 16, ...

Which term in the A.P. 1, 6, 11, 16,..... is 301 ?

If 1 + 6+11 +16+…+x= 148 then x=