" ख) "x^(2)-2x-8" Are the origin of "

| x ^ (2) -2x-8 | = 2x

If the transformed equation of a curve when the origin is translated to (1,1) is X_( riginal )^(2)+2X-Y+2=0 then the original equation of the curve is

(3,-4) is the point to which the origin is shifted and the transformed equation is X^(2)+Y^(2)=4 then the original equation is (A) x^(2)+y^(2)+6x+8y+21=0 (B) x^(2)+y^(2)+6x+8y-21,=0 (C) x^(2)+y^(2)-6x+8y+21=0 (D) x^(2)+y^(2)-6x-8y+21=0

To remvoe the first dgree terms in the equation 4x^(2)+9y^(2)-8x+36y+4=0 , the origin in shifted to the point

The angle between y^(2)=x and x^(2)=y at the origin is

The angle between the parabolas y^(2)=x and x^(2)=y at the origin is-

Angle between y^(2)=x and x^(2)=y at the origin is

In order to eliminate the first degree terms in the equation 2x^(2)-2y^(2)+z^(2)-4x+8y+2z-5=0 the origin should be shifted to the point

8x^(3) - 2x =?