" 4.(a) "y=2x

Draw the graphs corresponding to the equations (a) y = 4x (b) y =-6x (c) y = x +4 (d) y =-2x +4 (e) y = 2x - 4 (f) y =- 4x -6

The solution of the differential equation (dy/dx)^2-(xdy)/dx+y=0 is (A) y=2 (B) y=2x (C) y=2x-4 (D) y=2x^2-4

x ^(2), -4y ^(2) -2x + 16 y -40=0 reprsents

x ^(2) -4y ^(2) -2x + 16 y -40=0 reprsents

The area bounded by the parabolas y=4x^(2), y=(x^(2))/(9) and the straight line y = 2 is

The area of the region bounded by the curves x^(2)+4y^(2)=4 " and " 4y^(2)=3x is

x^3 X\ 4x y^2 X3/2x y^3=\ .............