Show that : `(3x+7)^2-84 x=(3x-7)^2` `(9a-5b)^2+180 a b=(9a+5b)^2` `((4m)/3-(3n)/4)^2+2m n=(16 m^2)/9+(9n^2)/(16)`

Show that: :(3x+7)^(2)-84x=(3x-7)^(2)(9a-5b)^(2)+180ab=(9a+5b)^(2)((4m)/(3)-(3n)/(4))^(2)+2mn=(16m^(2))/(9)+(9n^(2))/(16)

Show that ((4m)/3-(3n)/4)^2 +2mn = 16/9m^2+9/16 n^2

Show that. (i) (3x+7)^2-84x=(3x-7)^2 (ii) (9p-5q)^2+180pq=(9p+5q)^2 (iii) (4/3(m)-3/4(n))^2+2mn=16/9(m^2)+9/16(n^2) (iv) (4pq+3q)^2-(4pq-3q)^2=48pq^2 (v) (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0

Show that: (4/3m-3/4n)^2 +2mn=(16)/9m^2+9/16n^2

Show that.(i) (3x+7)2-84x=(3x-7)2( ii) (9p-5q)2+180pq=(9p+5q)2( iii) (43(m)-34(n))2+2mn=169(m2)+916(n2)( iv )(4pq+3q)2-(4pq-3q)2=48pq2(v)(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0

Show that : (2/3 m+ 3/2 m)^2 - 2mn = 4/9 m^2 +9/4 n^2 .

Show that: (frac(4)(3)m -frac(3)(4)n)^2 + 2mn = frac(16)(9) m^2 + frac(9)(16)n^2

Find m so that (2/9)^3x\ (2/9)^(-6)=(2/9)^(2m)^(-1)

Expand: (i) (8a + 3b)^(2) (ii) (7x + 2y)^(2) (iii) (5x + 11)^(2) (iv) ((a)/(2) + (2)/(a))^(2) (v) ((3x)/(4) + (2y)/(9))^(2) (vi) (9x - 10)^(2) (vii) (x^(2) y - yz^(2))^(2) (viii) ((x)/(y) - (y)/(x))^(2) (ix) (3m - (4)/(5) n)^(2)