2sin^(2)theta+sin^(2)2 theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=

The angle between the pair of straight lines y^(2)sin^(2)theta-xy sin^(2)theta+x^(2)(cos^(2)theta-1)=0 is

The angle between the pair of straight lines y^(2)sin^(2)theta-xy sin^(2)theta+x^(2)(cos^(2)theta-1)=0 is

The root(s) of the expression 2sin^2 theta + sin^2 2theta=2 is

The number of values of theta in [(-3pi)/(2), (4pi)/(3)] which satisfies the system of equations. 2 sin^(2) theta + sin ^(2) 2 theta = 2 and sin 2 theta + cos 2 theta = tan theta is

The number of values of theta in [(-3pi)/(2), (4pi)/(3)] which satisfies the system of equations. 2 sin^(2) theta + sin ^(2) 2 theta = 2 and sin 2 theta + cos 2 theta = tan theta is

The angle between the pair of straight lines y^(2)sin^(2) theta -xy sin^(2)theta +x^(2)(cos^(2)theta-1) =0 is