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" (iii,"7log(15)(16)/(15)+5log(25)/(24)+...

" (iii,"7log_(15)(16)/(15)+5log(25)/(24)+3log(81)/(80)

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7log((10)/(9))-2log((25)/(24))+3log((81)/(80))

show that 7log((16)/(15))+5log((25)/(24))+3log((81)/(80))=log2

The value of 7log((16)/(15))+5log((25)/(24))+3log((81)/(80))=

7log((10)/(9))-2log((25)/(24))+3log((81)/(80))=log2

If 7"log"_(a)(16)/(15)+5"log"_(a)(25)/(24)+3"log"_(a)(81)/(80)=8 , then a=

prove that log2+16log((16)/(15))+12log((25)/(24))+7log((81)/(80))=1