If `(tan(alpha+beta-gamma))/("tan"(alpha-beta+gamma))=(tangamma)/(tanbeta),(beta!=gamma)` then `sin2alpha+sin2beta+sin2gamma=` (a)`0` (b)` 1` (c) `2 `(d)`1/2`

If (tan(alpha +beta - gamma))/(tan(alpha -beta + gamma)) = (tan gamma/tan beta) show that sin(beta -gamma) =0 or sin(beta -gamma) =0 , or sin2 alpha +sin2 beta + sin2 gamma =0

If tan beta=(tan alpha+tan gamma)/(1+tan alpha tan gamma)* prove that sin2 beta=(sin2 alpha+sin2 gamma)/(1+sin2 alpha sin2 gamma)

Prove that: tan(alpha-beta)+tan(beta-gamma)+tan (gamma-alpha) = tan(alpha-beta) tan (beta-gamma) tan (gamma-alpha) .

If alpha+beta-gamma=pi , then sin^(2)alpha=sin^(2)beta-sin^(2)gamma is equal to

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and gamma are in

If 0

If cos(alpha + gamma)/cos(alpha - gamma) = cos 2beta then tan alpha, tan beta and tan gamma are