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(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+...

`(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)`

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Using appropriate properties find. (i) -(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(1)/(6) (ii) (2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(4)/(5)times((-2)/(3))-(2)/(5)times(1)/(3)+(3)/(5)times(4)/(5)=

(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(2)/(5)times((-3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

(-3)/(4)times{(2)/(3)+((-5)/(6))}

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

Evaluate : 5^(6)times(1)/(5^(2))times(6^(2))/(1)times(1)/(3^(2)

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

[((3)/(4))^(3)]-:((3)/(4))^(2)times((1)/(3))^(-2)times3^(-1)times((1)/(6))^(-1)