Find the least positive value of `x` satisfying `(sin^2 2x+4sin^4x-4sin^2xcos^2x)/4=1/9`

Explanation

`(sin^2 2x+4sin^4x - 4sin^2xcos^2x)/4 = 1/9`

`=>((2sinxcosx)^2+4sin^4x - 4sin^2xcos^2x)/4 = 1/9`

`=>(4sin^2xcos^2x+4sin^4x - 4sin^2xcos^2x)/4 = 1/9`

`=>(4sin^4x)/4 = 1/9`

`=>sin^4x = 1/9`

`=>sinx = +-1/sqrt3`

So, least positive value of `x` will be `sin^-1(1/sqrt3).`