Let A,B,C, be three angles such that `A=pi/4` and `tanB tanC=pdot` Find all possible values of `p` such that `A , B ,C` are the angles of a triangle.

Explanation

`A+B+C=pi`

`B+c=pi-pi/4`

`B+C=3/4pi`

`0<=B,C<=3/4pi`

`tanB*tanC=P`

`sinB/cosB*sinC/cosC=P/1`

`(sinBsinC+cosBcosC)/(sinBsinC-cosBcosC)=(P+1)/(P-1)`

`(cos(B-C))/(-cos(B+C))=(P+1)/(P-1)`

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