If `E.tan(x-30^@)=J.tan(x+120^@),` then `(E+J)/(E-J)=`

If E * tan (x-30 ^ (@)) = J * tan (x + 120 ^ (@)) then (E + J) / (EJ) =

tan (e^x+5)

int e^(x)tan e^(x)dx

int (e ^ (x) tan x + 1) / (tan x)

int e^(x)tan(e^(x))dx

e^(tan^(-1)x)log(tan x)

The solution of differential equation (1+y^2)+((x-2e^tan^((-1)y))dy)/(dx)=0 is (x-2)=k e^tan^((-1)y) x e^t a n-1y=e^2tan^((-4)y)+k x e^tan^((-1)y)=tan^(-1)y+k x e^2tan^((-1)y)=e^2tan^((-1)y)+k

If y=tan^(-1)((2)/(e^(-x)-e^(x)))" then "(1+e^(2x))y_(1)=

e^(x) sec x ( 1 + tan x )